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  1. Python: copy of a variable - Stack Overflow

    2012年11月24日 · a='hello' b=a #.copy() or a function that will make a copy a='bye' # Is there a way to make # 'b' equal 'a' without # doing 'b=a' print a print b I am having a problem using the …

  2. python - Copied variable changes the original? - Stack Overflow

    aux = copy.deepcopy(matriz) As an aside, you don't need semi-colons after each statement, python doesn't use them as EOL markers.

  3. python - copy variable by value not reference - Stack Overflow

    2018年11月9日 · 7 quite new to python and struggling to achieve a value copy of a variable. have an algorithm that calls recursively another one but not getting the desired values since i think …

  4. python: changes to my copy variable affect the original variable

    2013年11月13日 · 93 That is because in python setting a variable actually sets a reference to the variable. Almost every person learning python encounters this at some point. The solution is …

  5. How can I create a copy of an object in Python? - Stack Overflow

    2011年1月25日 · To get a fully independent copy of an object you can use the copy.deepcopy() function. For more details about shallow and deep copying please refer to the other answers to …

  6. python - How do I clone a list so that it doesn't change …

    Here in the image list_1 and copy are two variable names, but the object is same for both variable which is list. So if you try to modify copied list then it will modify the original list too because …

  7. python - When is a variable passed by reference and when by …

    36 Everything in Python is passed and assigned by value, in the same way that everything is passed and assigned by value in Java. Every value in Python is a reference (pointer) to an …

  8. How to copy variable and not change it, python [duplicate]

    2022年3月20日 · How to copy variable and not change it, python [duplicate] Asked 3 years, 4 months ago Modified 3 years, 4 months ago Viewed 2k times

  9. python - Copy a dictionary into a new variable without maintaining …

    2012年1月7日 · I want to copy a dictionary into a new variable without maintaining the link with previous variable.

  10. python - What is the difference between shallow copy, deepcopy …

    2017年5月6日 · 479 Normal assignment operations will simply point the new variable towards the existing object. The docs explain the difference between shallow and deep copies: The …