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  1. 123

    A palindrome number is a number that remains the same when its digits are reversed (e.g., 121, 1331, 45654). Using a for loop, we can compare digits from the start and end moving towards the center to check if they match.

    Example:

    # Palindrome check using for loop
    num = input("Enter a number: ")

    is_palindrome = True
    for i in range(len(num) // 2):
    if num[i] != num[-(i + 1)]:
    is_palindrome = False
    break

    if is_palindrome:
    print(f"{num} is a Palindrome")
    else:
    print(f"{num} is not a Palindrome")
    コピーしました。

    How it works:

    • The number is taken as a string to easily access each digit by index.

    • The loop runs only till the middle (len(num)//2) since we compare symmetric positions.

    • If any mismatch is found, we break early for efficiency.

    • Time complexity is O(n/2) ≈ O(n) where n is the number of digits.

    Using a Function for Reusability:

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    ありがとうございました!詳細をお聞かせください
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