How are sin (x), tan (x), and x related graphically? How can I find the derivative of #y=c^x# using first principles, where c is an integer? What is the derivative of #log_e (x)#? What are the …

The derivative of this can be done with just the quotient rule, but you're free to give your answer simplified in many ways. d/ (dx) ( [3x - sinx]/ (cosx)) = [ (cosx ...

Focusing on # \frac {d} {dx} cos (sin 2x)#, we use the chain rule. Differentiate the outside function while leaving the inside function inside, then multiply by the derivative of the inside.

The answer is -sin (2)approx-0.035. One way to evaluate this limit is to use L'Hosptial's Rule. You can use L'Hospital's Rule whenever a limit is equal to 0/0 or oo/oo. The rule states that lim_ (x …

The second can now be evaluated as Deltaxrarr0: f' (x)=1* (1+tan^2 (x))/ (cos (0) (1-tan (x)tan (0)) Since cos (0)=1 and tan (0)=0: f' (x)= (1+tan^2 (x))/ (1 (1-tan (x)*0)) f' (x)=1+tan^2 (x) Which is a …

28 feb. 2017 · Derivative of the sine and cosine functions. First Derivative. How can I simplify this expression ?

y' = 0 We know that sin^2x + cos^2x = 1, therefore, y = 1. The derivative of a constant is 0, thus y' = 0. Hopefully this helps!

12 apr. 2016 · The derivative of #cos (x)# is #-sin (x)#. You can use that here, but you will have to use chain rule. # [3]" "=3* (-sin2x)*d/dx (2x)+d/dx (sin^2x)#

Explanation: From the given equation #f (x)=csc x- sin x# We determine #f'' (x)#, the second derivative of #f (x)#

So as you have stated the list of the derivatives are as follows: f (x) = sin (x +pi/5) f' (x) = cos (x +pi/5) f'' (x) = -sin (x +pi/5) f''' (x) = -cos (x +pi/5) Evaluating these at x=0 gives us the following …