SQL-Server-Management- / emade_dev_project_University_Country_ranking.sql Cannot retrieve latest commit at this time.

This function returns the rank of each row within a result set partition, with no gaps in the ranking values. The rank of a specific row is one plus the number of distinct rank values that come before ...

</pre><BR><BR>My method so far has been to select all clientIDs with multiple records (group by clientid having count(*) > 1) and using a cursor + dynamic SQL to insert all the records for a given ...

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